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16 < 2x + 4 < 4 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution. please help me!!!!!!!!!
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16 < 2x + 4 < 4 i.e. 16 -4< 2x < 4-4 i.e. 12< 2x < 0 i.e. 12/2< x < 0/2 i.e. 6< x < 0 Graph of the given inequality intersects the X-axia at x=6 and is parallel to Y axis
the graph is one a number line
is it an open circle, and which way Is the shading/
Please check for typo. In \( 16 < 2x + 4 < 4\) 16 cannot be less than 4.
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