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integral of 3x^2 4sprt of 9+3x^3 dx
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depending on notation .... try a by parts run; poly go to zero rather easily
do a substitution of u=9+3x^3 then du =.... ? (in your question,combine the x^2 with dx)
\[\huge \int {3x^2~\sqrt[4]{9+x^3}dx}\] is it ?
that does make it easier to assess :)
you could write the integral as integral of (9+x^3)^1/4 dx^3
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Try u substitution. \[u = 9+ x ^{3}\] \[\frac{ du }{ dx } = 3x ^{2}\] \[du = 3x^{2} dx\] then \[\int\limits_{?}^{?} \sqrt[4]{u} du\]
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