Question

use the elimination method to solve the system of equations
5u+2v=-18
3u+v=-6

Answer 1

Would you like to get rid of the u or the v? One is easier than the other.

Answer 2

@jabberwock i just tying to solve the problem

Answer 3

@uri

Answer 4

Alright, let's get rid of the v. You have 2v in the first equation and v in the second. You want the coefficients to be opposites of each other. So you want to multiply everything in the second equation by -2.

Answer 5

5u+2v=-18
3u+v=-6

Multiply the 2nd eq by -2
So,

5u+2v=-18
-6u-2y=12
=========

Solve this.

Answer 6

2y? @uri

Answer 7

It's 2v*

Answer 8

1u=6

Answer 9

Always remember the sign of greater number comes so it's -6+5=-1 and -18+12=-6

So,-1u=-6

Answer 10

Now divide -6 with -1

Answer 11

-6

Answer 12

Aha..-6/-1 double negative=positive.

So,u=6

Answer 13

@uri right u=6

Answer 14

Now we have u,Lets solve for v,Put the value of u i.e 6 in original eq 2..So,
3u+v=-6
3(6)+v=-6

Solve it.

Answer 15

18+v=-6, v=3

Answer 16

@uri

Answer 17

3(6)+v=-6
18+v=-6
v=-6-18
v=-24.