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Do I have the answer? Six 6-sided dice are rolled. What is the probability that the number of dice showing even numbers and the number of dice showing odd numbers is equal?
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Can someone please confirm? I just used the binomial theorem
@satellite73 Can I even use the binomial theorem here?
I think it would be 20*(1/2)^6?
In other words, 6c3*(1/2)^3*(1/2)^3
Yes, this is a binomial distribution. So P(3)=C(6,3)(1/2)^3(1/2)^3 =20(1/2)^6 as you had it.
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Its correct, thanks.
You're welcome!
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