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simplify x^4-3x^3 over x^2-9
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\[\frac{ x^4-3x^3 }{ x^2-3^2 }=\frac{ x^3(x-3) }{ (x+3)(x-3) }=\frac{ x^3 }{ x+3 }\]
hope that helps you
yes thank you i had factored it wrong
its alrite ;)
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