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The solutions to the inequalities 0≤x≤2,0≤y≤1, and y≤−12x+32 form a polygonal region in the plane. How many sides does this polygon have?
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Have you considered graphing the lines? Having you considered finding their intersections?
i graphed the lines and i figured it was three but the correct answer is f ive. i just dont know how to get 5
Are you forgetting the x-axis and the y-axis? It's not a closed polygon without those.
yeah i included them
That does not make sense. You should have x = 0 x - 2 y = 1 y = 0 That's four. Now add the last line and it should cut off a corner and make the 5th side.
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got it! thank you
Good work!
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