Alice put $68,000 in two different accounts. One account pays 6.5% and the other 7% interest. If the total amount earned in one year is $4,535, how much did she invest in each account?
Just solve the system of equations in 2 variables. .065x + .07y = 4535 x+y=68000
How do I solve the first equation?
It's a system of equations. You solve them together.
You solve them both at once. By substitution
.065x^2+.07y^2=72535???????????
No
did I do that correct?
Am I way off?
4535 * 7 4535 * 65???
68000+4535=72535?
.065x + .07y = 4535 x+y=68000 use the second equation, x+y=68000, to rearrange for y=, to get: y = 68000-x Now, replace y in the first equation with that: \[\Large .065x + .07(68000 - x) = 4535\]
.065x+476-.07x=4535??
if you meant... \[\Large .065x+4760-.07x=4535\]Then it looks good so far (you had a 476 not 4760). Now try solving that for x. It might help to first rearrange the order like so: \[\Large .065x-.07x +4760 =4535\]
.06x-.07x=-225
how does that look?
Well.. close, but now you dropped another number... \[\Large .065x-.07x=-225 \] Now just combine the x terms and find x.
add .07 to each side? add .065 to each side?
No, combine like terms. For example, 2x + 3x = 5x, or 4x - 7x = -3x. Combine the 0.065x-0.07x to get...?
.135
One is being subtracted from the other...
.005=-225
.005x=-225
0.065x - 0.07x doesn't equal 0.005x, but you're close... be careful with negatives.
-.005x=-225
Correct. Now find x.
=45000
x=45000
is 45000 6.5%??
.065x + .07y = 4535 yep, since it has the 0.065 in front.
23000 is 7%??
Yep.
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