Question

The sum of four consecutive multiples of 5 is 210
What is the larger and smaller integer?

I know the answers but i need an equation to get full credit

Answer 1

Let 5n be the first (smallest) multiple of 5, where n is some whole number. The the other three are:
5n+5
5n+10
5n+15

Now, the sum of these four must be 210, so:
(5n)+(5n+5)+(5n+10)+(5n+15)=210

Answer 2

Thank you so much