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Mathematics 14 Online
OpenStudy (anonymous):

Determine the intervals on which the function is increasing, decreasing, and constant.

OpenStudy (anonymous):

OpenStudy (anonymous):

Increasing on x > 1; Decreasing on x < 1 Increasing on x < 1; Decreasing on x > 1 Increasing on x > 0; Decreasing on x < 0 Increasing on x < 0; Decreasing on x > 0

OpenStudy (anonymous):

Haha pleaseeee help me, it's my last question

OpenStudy (primeralph):

@lornbeach You know I'll ask what you think it is.

OpenStudy (anonymous):

I know, but I honestly have no clue haha

OpenStudy (primeralph):

Well, as I said, you got to beg me to answer. |dw:1375544155131:dw|

OpenStudy (anonymous):

Whyy ?

OpenStudy (primeralph):

Just for the fun of it. Now beg!!!

OpenStudy (anonymous):

Umm please answer my math question

OpenStudy (primeralph):

No, it's like this: Pleeeeeaaaaassssssseeeeee Your Lordship.

OpenStudy (anonymous):

Hahahahha please your lordship, answer my question. You're the only one who can help mee

OpenStudy (primeralph):

That's much better.

OpenStudy (anonymous):

Why thank you (:

OpenStudy (primeralph):

The graph is going up for x >0 and going down form x>0. So, which option is that?

OpenStudy (anonymous):

I don't think that's an option

OpenStudy (primeralph):

Up = Increasing. Down = Decreasing. You didn't expect me to say the direct answer, did you?

OpenStudy (anonymous):

I know that, but there isn't an option that says " increasing x > 0; decreasing x > 0

OpenStudy (primeralph):

Corrected. The graph is going up for x <0 and going down form x>0.

OpenStudy (anonymous):

So it is the last one

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