Question

The perimeter of a rectangle is 34yd and the area of the rectangle is 60yd^2 Find the dimensions of the rectangle

Answer 1

what are the answers?

Answer 2

i need to know the answers can you help me

Answer 3

is there any answers with the question?

Answer 4

not that I know of.

Answer 5

is it a 3D rectangle?

Answer 6

No it doesn't say

Answer 7

that's all the questions states

Answer 8

perimeter = 2x + 2y = 34
area = xy = 60

use substitution: from area we have y = 60/x so plug that in for y in the perimeter equation:

2x + 2(60/x) = 34

2x + 120/z = 34

multiply all by x

2x^2 -34x + 120 = 0
x^2 - 17x + 60 = 0
(x - 12)(x - 5) = 0

x is either 12 or 5

plugging those into xy = 60

y = either 12 or 5.

that's your answer. either (x, y) = (12, 5) or (x. y) = (5, 12). both true

Answer 9

pretty much one answer though: a 5 by 12 rectangle

Answer 10

thank you so much

Answer 11

glad i could help lol