The perimeter of a rectangle is 30yd , and the area of the rectangle is 54yd^2 . Find the dimensions of the rectangle

Question

The perimeter of a rectangle is 30yd , and the area of the rectangle is 54yd^2  . Find the dimensions of the rectangle

mathmate · Answer

Perimeter = 2(length+width) =30
so
length+width=15
Area = length*width = 54
We are looking for two numbers which when multiplied together give 54 and added together give 15.
Can you find the two numbers?

aivantettet26 · Answer

P = 30
A = 54
P = 2L + 2W
A = LW

aivantettet26 · Answer

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aivantettet26 · Answer

Substitute the L = 54/W to the equation of the Perimeter

aivantettet26 · Answer

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aivantettet26 · Answer

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aivantettet26 · Answer

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aivantettet26 · Answer

Therefore we conclude that there are two possible dimensions
W = 9 and L =12
OR
W = 6 and L = 18

mathmate · Answer

A minor correction:
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