Question

The perimeter of a rectangle is 30yd , and the area of the rectangle is 54yd^2 . Find the dimensions of the rectangle

Answer 1

Perimeter = 2(length+width) =30
so
length+width=15
Area = length*width = 54
We are looking for two numbers which when multiplied together give 54 and added together give 15.
Can you find the two numbers?

Answer 2

P = 30
A = 54
P = 2L + 2W
A = LW

Answer 3

Substitute the L = 54/W to the equation of the Perimeter

Answer 4

Therefore we conclude that there are two possible dimensions
W = 9 and L =12
OR
W = 6 and L = 18

Answer 5

A minor correction: