Question

How would I solve 8=√2^4x-8?

Answer 1

Is everything on the right side a square root?
Does the equation read
8= Square root (2^4x-8) ?

Answer 2

Assuming the equation is
8= Square root (2^4x-8) then we square both sides:
64 = 2^4x -8
72 = 2^4x taking logs of both sides
log (72) = 4x * log (2)
1.8573324964 = 4x * 0.3010299957
6.1699250014 = 4x

x = 1.5424812504

Answer 3

Thanks.