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Simplify completely:
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wait so do i divide or add?
6x^4 +9x^2 +12x 3x is the GCF.
3x(3x^3+3x+6)
wait if its polynomials you use gcf too?
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\[\frac{4+2}{2}=\frac{4}{2}+\frac{2}{2}=2+1=3\]\[\frac{4+2}{2}=\frac{6}{2}=3 \]3x goes into the first term, 2x^3 with no remainder. 3x goes into 9x^2, 3x with no remainder. 3x goes into 12x, 4 with no remainder.\[\frac{6 x^4+9 x^2+12 x}{3 x}=2 x^3+3 x+4 \]
I have totally forgotten my tables..Like seriously...:o i feel bad now..it's 3(2x^3+3x+4)
@Auri Thank you for the medal.
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