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factor completely: below:
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\[4ac ^{32}(3a ^{2}+4b ^{10})^{2}-5b(3a ^{2}+4b ^{10})^{2}\]
@Algebra2013 \[\huge \bf (3a^2+4b^{10})^2\] is common.. Now, take this and divide whole equation:- we get \[\huge \huge \bf (3a^2+4b^{10})^2[4ac^{32}-5b]\] ^^^ This is your complete answer
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