Question

[(radx+4)+(radx-1)]^2

Answer 1

\[(\sqrt{x+4} - \sqrt{x-4})^{2}\]

Answer 2

\[(a-b)^{2} = a^{2} -2ab + b^{2}\]

a = \[\sqrt{x + 4}\]

b = \[\sqrt{x-1}\]

Answer 3

well at the top it says (radx-1) and below it says (radx-4) which one is it really?

Answer 4

top

Answer 5

than just do what I said instead

b = \[\sqrt{x-4}\]

Answer 6

okay, thanks!