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Find the measure of angle N
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let's see what's the sum of interior angles for a polygon => \(\bf (sides -2 ) \times 180\)
540
that's a pentagon, 5 sides, thus (5-2)* 180 => 3*180 = 540
at the bottom of the shape, we have 2 90 degrees ones so the remaining 3 angles sum is 540-(2 * 90) = 360
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and we know those angles sum add up to 360 then so the angles are 17x+4 10x-10 and 18x+6 thus ( 17x+4 ) + ( 10x-10 ) + ( 17x+4 ) = 360 # solve for "x" then replace in 18x+6 to get angle N
darn, talk about typos :(
( 17x+4 ) + ( 10x-10 ) + ( 18x+6 ) = 360
8
replace in 18x+6 to get angle N :)
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150
:)
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