Question

What are the solutions of 6x2 = 12x? Please explain to me how to do this, and not just the answer thx :)

Answer 1

you can make it equal to zero,

6x^2-12x=0

then factor

Answer 2

6x^2-12x=0
+12x 12x
6x^2=12x now what

Answer 3

you reverted back to the original format given.

you need to factor out the x

6x^2-12x=0

x(6x-12)=0

then x=0, and

6x-12=0 -> x=12/6=2

Answer 4

do I plug x back in?

Answer 5

nope, you're trying to find what the values (roots) of x are. The roots are where the graph crosses the x axis.

Answer 6

x = 0, x = −2

x = 0, x = 2

x = 6, x = 2

x = 6, x = −2

Answer 7

gosh im not getting this at all

Answer 8

dont stress and think about it.

you have: 6x^2=12x

you need to make it equal to zero to find the values of x.

6x^2-12x=0

then you factor the x out,
x(6x-12)=0

so x=0 and 6x-12=0

just solve second part from the bracket and thats your second root.

Answer 9

6x^3-12x=0

Answer 10

becuase x*6x=6x^2 x*-12=-12x

Answer 11

6x^3=12x is the actual question?

Answer 12

the question is [9.02] What are the solutions of 6x2 = 12x?

x = 0, x = −2

x = 0, x = 2

x = 6, x = 2

x = 6, x = −2

Answer 13

okay, so as i said, make it equal to zero:

6x^2=12x

subtract 12x from both sides

6x^2-12x=0

factor out 1 of the x's (because you can't factor both)

you can also factor out 6,

6x(x-2)=0

so you have:
6x=0 and x-2=0

Answer 14

now you need to solve for x (by isolating it)

Answer 15

I thought you have to do the opposite of what the sign tells you, the -12 so I would have to add from both sides to cancel out

Answer 16

well yes, if you have

x-12=0

to isolate x, you add 12 to both sides

x-12+12=12

x=12

is that what you're getting at?

Answer 17

how to I give you a medal or something on here for being so patient (new to this site) sorry but could you please sjow me how to solve it all together, with step 1 , 2 ect

Answer 18

no problem, if i wasn't patient i wouldn't be helping ya lol

you have: 6x^2=12x

you wanna make it equal to zero to solve for x.

bring the 12x to the other side, since it's positive it's adding

notice that if you wanted to isolate the x, like this

6x^2/12=x

then yes you would divide.

but thats not what were doing.

6x^2-12x=12x-12x -> 6x^2-12x=0

makes sense?

Answer 19

yes, ok so you made it so it would equal 0

Answer 20

now we factor what we can

6x^2-12x=0

factor the x from both 6x^2 and -12x

x(6x-12)=0

we can also factor the 6

6x(x-2)=0

now we can separate them since both parts when multiplied equal zero

6x=0 and x-2=0

now it's just a matter of isolating x

Answer 21

I isolate what? :O

Answer 22

isolate x from "6x=0" and "x-2=0"

Answer 23

so x=6 and x=2

Answer 24

6x=0

divide both sides by 6

6x/6=0 -> x=0

Answer 25

no, here 6x is multiplied, you need to divide both sides by 6

Answer 26

6/x

Answer 27

nononono

6x=0 -> 6x/6=0/6 right?

Answer 28

you're doing it as if it was x-6=0, which is not the case

Answer 29

I'm about to jump out a window ... jk but for real I am sooo lost it seems so simple but math is so confusing D;

Answer 30

you're getting confused with the algebraic operations of when to divide/multiply and when to subtract/add. haha id suggest you review those concepts

Answer 31

ok so , the answer is 6x=0 -> 6x/6=0/6

Answer 32

Nvm I feel bad, haha I dont want to waste youre time any more

Answer 33

lol don't worry about it.

yes, the roots are 6x/6=0/6 -> x=0 and x=2

Answer 34

do you understand it? or what do you not understand?

Answer 35

after that what do I need to do?

Answer 36

thats it x=0 and x=2 are the roots, which is what you were looking for

Answer 37

I feel so dumb, ok thank you for your help!!! you rox :)

Answer 38

haha you're not dumb. all you need is practice, so practice some more! :)