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factor completely: see below:
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\[18a ^{6}b ^{2}r ^{4}y ^{3}-3a ^{2}b ^{5}r ^{2}z+6ab ^{3}c ^{2}-12a ^{4}b ^{3}c\]
GCF is 3?
To do a problem like this you must break upinto two parts
\[3ab ^{2}\]
So like do the first two first
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I gotta go!!
the answer I got is\[3ab ^{2}(6a ^{5}r ^{4}y ^{3}-ab ^{3}r ^{2}z+2bc ^{2}-4a ^{3}bc)\]
this one looks messy...
hmmm
so you don't agree with my answer??
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i agree with what you have so far, but I think the problem is a messy one
lol umm ok
you got it. I put it in wolframalpha and it said it doesn't simplify past that.
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