Question

Find the equation of the straight line when gradient =2/5 and passes through point (0,-1)

Answer 1

ok sort of like last time, but now they do not give us the y intercept
we know the gradient so
y = (2/5)x+b
now we use the point they gave to find b
(0,-1) so when x = 0, y = -1
so
y=(2/5)x+b
becomes
-1 = (2/5)(0)+b
what is b?

Answer 2

Is b 0/5?

Answer 3

\[-1=\frac{2}{5}*0+b\]
what is b?

Answer 4

0*(2/5) = 0

Answer 5

I see now :) thanks!

Answer 6

word
\[y=\frac{2}{5}x-1\]