Question

(7x-3)^((1)/(4))+3=0

Answer 1

You can write the equation as:\[(7x-3)^{1/4}=-3\]

Answer 2

Now to remove the 1/4 exponent in the LHS, raise both sides of the equation by 4. You get: \[(7x-3)=(-3)^{4}\]

Answer 3

Now simplifying, we get: \[7x=84\]

Answer 4

Solving which you can get \[x=12\]