Question

Find the equation for the straight lines which passes through points (-7,3) and (2,4).. I think x= 1/9 and y might = 1 1/9?

Answer 1

\[slope = \frac{x_1-x_0}{y_1-y_0}\]
after you find slope, do the same thing we did last time ( you can choose either point) to find b

Answer 2

That's what I did.. Is this the right answer??

Answer 3

Which the equation would be y=1/9x+1 1/9?

Answer 4

*1 3/9 sorry

Answer 5

ahh one sec
m = 1/9
y = (1/9)x+b
so
4=(1/9)2+b
4=(2/9)+b
b=4-(2/9)
b=36/9-2/9
b=34/9
y = (1/9)x+(34/9)

Answer 6

you can also use
(y-y_0)=(x-x_0)m
y-4=(x-2)(1/9)
y = (1/9)x-(2/9)+4
y=(1/9)x-(2/9)+36/9
y = (1/9)x+(34/9)

Answer 7

Thanks! I just left out the last step :)