Mathematics
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OpenStudy (anonymous):
multiply and simplify: x+3 * x+4
----- ------------
x x^2+7x+12
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OpenStudy (ivettef365):
do you know how to solve x^2+7x+12 ??
OpenStudy (anonymous):
noo :/
OpenStudy (ivettef365):
ok, you need to find a multiple of 12 that when you add = 7 ?
OpenStudy (ivettef365):
that would be 4 x 3 = 12 and 4 + 3 = 7
OpenStudy (anonymous):
ohh okay isee
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OpenStudy (ivettef365):
so to solve that would be (x+4)(x+3)
OpenStudy (anonymous):
okayy now what
OpenStudy (anonymous):
x^2+7x+12
=X^2+3x+4x+12
=x(x+3)+4(x+3)
=(x+4)(x+3)
OpenStudy (ivettef365):
so now you have
x+3 x+4
----- . --------
x (x+3)(x+4)
OpenStudy (anonymous):
okay
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OpenStudy (ivettef365):
now you can cancel and what do you have left ?
OpenStudy (anonymous):
what do i cancel
OpenStudy (anonymous):
{(x+3)/x}*{x+4/(x+4)(x+3)}
x is ur answer after all cancellation
OpenStudy (anonymous):
so how would i write the final answer
OpenStudy (ivettef365):
what is the same from top and bottom
that is like if I have 4/4 that would be = 1
actually you are not cancelling you are converting to 1
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OpenStudy (anonymous):
ohhhh
OpenStudy (anonymous):
so how would i write the final answer
OpenStudy (anonymous):
cause what that other guys said confused me lol
OpenStudy (ivettef365):
you have left the following
1 1
------- . ------- = ? just multiply and what do you get ?
x 1
OpenStudy (anonymous):
1
----
1x
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OpenStudy (ivettef365):
correct, which is the same as 1/x
OpenStudy (anonymous):
okay, thank you for teaching me i kinda understand it now :)
OpenStudy (ivettef365):
yw :)