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How do i factor 8x^3-27?
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a^3 - b^3 = (a - b) * (a² + ab + b²) a = 2x and b = -3 <=> (2x)^3 - (-3)^3 = (2x - (-3)) * ((2x)² + (2x * (-3)) + (-3)²) = (2x + 3) * (4x² - 6x + 9)
medal plzz :)
hopefully u get the process
Nice @britbrat4290
You can do (2x + 3) * (4x² - 6x + 9)
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yea u can do it a couple ways
And that will be your required answer
ty @Paynesdad :)
So I can solve (2x + 3) * (4x² - 6x + 9)
There is no solving it is just factoring it.
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You can't solve something unless it is an equation or an inequality
How do i come up with the answer? Like its 8x^3-27 but i dont see the GCF so how do i factor now?
How did i get 2 for the x?
if u do the math
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