Question

cansomeone plz help me...
Simplify completely 12x+36/x^2-4x-21 and find the restrictions on the variable.

Answer 1

@dumbcow
@abb0t

Answer 2

factor numerator , denominator.
simplify them
the restriction is the value of x which makes denominator = 0. that means you have to solve for x ( from the denominator)

Answer 3

i got x+3/x-7 \[x \neq7\],\[x \neq-3\]

Answer 4

for my answer is that right

Answer 5

nope

Answer 6

ok i will try again

Answer 7

\[\frac{12x+36}{x^2-4x-21}=\frac{12(x+3)}{(x+3)(x-7)}=\frac{12}{x-7}\]
so restriction is x-7=0 or x = 7
the solution is just x \(\neq7\)