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Algebra
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how would i solve this? w^2=9
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what do you think?
would i need to get it to this w^2-9=0?
good, then?
that's where i get confused. would it be (w-1)(w+9)
nope, apply \[a^2 -b^2= (a+b)(a-b)\]your a is w and your b is 3
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so its (w+3)(w-3) that makes sense.
yup
then?
w=-3 and w=3
medal for you
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thank you!!!
yw
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