Question

(6sec180-4cot90)^2

Answer 1

Re-write as:\[\bf \left( 6\frac{ 1 }{ \cos(180) } -4\frac{ \cos(90) }{ \sin(90) }\right)^2=??\]

Answer 2

\[(6\text{Sec}[180{}^{\circ}]-4\text{Cot}[90{}^{\circ}])^2=(-6-0)^2=36 \]