Question

Identify the 35th term of an arithmetic sequence where a1 = -7 and a18 = 95.

Answer 1

18 is a subscript btw.

Answer 2

this is sometimes simpler if we start the index at a0

a0 = -7 + d(0)
a1 = -7 + d(1)
a2 = -7 + d(2)
a3 = -7 + d(3)
a4 = -7 + d(4)
etc ...

our goal is to determine the value of d

Answer 3

a18 then shifts its index as a17 and we have:

95 = -7 + d(17)

Answer 4

our goal is to determine the value of a35 shifted is: a34

a34 = -7 + d(34)

Answer 5

so when it shifts, it just goes down by one?

Answer 6

you can shift it by any amount your heart desires; i chose to shift it down by 1 is all to avoid the whole d(n-1) construction in favor of dn

Answer 7

spose your given a12 and a57

we would then whose to shift it down by 12 ....

Answer 8

1)203
2)197
3.)168
4.) 163
these are my choices just don't know now i would get to a number with no variable

Answer 9

*then chose...

Answer 10

solve for d: 95 = -7 + d(17)

then use it to solve for: a34 = -7 + d(34)

Answer 11

can you explain further? please, sorry I'm like really bad with this

Answer 12

its just algebra ...

95 = -7 + d(17) ; what value of d (or would you perfer it to be called x?) makes this work

Answer 13

i got 6!

Answer 14

a34 = -7 +6(34 )

Answer 15

a34=197

Answer 16

excellent :)

Answer 17

thank you so much! i get this now!!!

Answer 18

practice helps :)

Answer 19

just got 100 on my quiz! whooooo