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Determine the zeros of f(x) = x4 – x3 + 7x2 – 9x – 18.
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I don't understand how to do this one @phi
± factors of 18: ± 1,2,3,6,9,18 so try and see if you can find a root
2
now do synthetic division
x^3+x^2+9x+9=0
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yes, now try to find a root for this using ±1,3,9
-1
sy
ok, now syn div on the cubic
okay
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x=+/-3
almost you should have gotten x^2 +9 = 0 did you ?
yeah
*x=+/-3i sorry
then x^2= -9 now as you know, there is no real number that when you square it is *negative*
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yes, looks good
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