Question

find cos 0 if sin 0= -5/13 and tan 0>0

Answer 1

cos ^2 = 1-sin^2
Now as tan >0 and sin <0 this is 3rd quad where cos is also <0

Answer 2

okay so what do I next because I have the choices of

-5/12
-13/5
-12/13
12/5

Answer 3

\(\bf sin(\theta) = -\cfrac{5}{13} \implies \cfrac{\textit{opposite side}}{\textit{hypotenuse}} \implies \cfrac{b}{c}\)

Answer 4

okay I understand that what do I do next

Answer 5

well, you want cosine, so \(\bf cos(\theta) = \cfrac{\textit{adjacent side}}{\textit{hypotenuse}} \implies \cfrac{a}{c}\)

Answer 6

put value of sin in the equation and solve
you will get cos^2 =1-25/169 Now you can solve from here