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find all solutions of the equation 2cos 3x =1 in the interval [0,pi).
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when does cos(t) = 1/2 ?
and check the interval, is that spose to be pi or 2pi
pi/3 and 5pi/3 thas wher cos 1/2
then 3x needs to be pi/3 or 5pi/3
the interval is 0,pi
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then when 3x = pi/3 is our only concern
2cos 3x =1 cos 3x =1/2 cos t =1/2, t = pi/3 3x = pi/3
thnks
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