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OpenStudy (anonymous):
What are the solutions of 4x2 = −20x?
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OpenStudy (ivettef365):
first you move the -20x to the other side by changing the sign to positive so you have 4x^2 + 20 = 0 4x (x+ 5) = 0 4x = 0 and x+ 5 = 0 so what are the 2 values for x
OpenStudy (anonymous):
0 and -5
OpenStudy (ivettef365):
correct
OpenStudy (anonymous):
thank u
OpenStudy (ivettef365):
yw :)
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