Question

Find the first six terms of the sequence.

Answer 1

\[ a _{1} = 6, a _{n} = 2 • a _{n}-1\]

Answer 2

should that say
\[a_{n+1} = 2a_n-1\]?

Answer 3

because the way you have it defined does not makes sense @aga3t

Answer 4

a_n = 2a_n-1
0=a_n-1
a_n = 1 is a contradiction

Answer 5

\[a=6,a _{n}=2∙a _{n-1}\] is what I meant

Answer 6

\[a_1 = 6\\a_2=2*a_1=2(6) = 12\\a_2=12\\a_3=2*a_2=2(12)=24\\a_4=2*a_3=......\]