Question

What is the product of 6the square root of the quantity 12 times k. • 4kthe square root of 3.? Simplify if possible.

Answer 1

help anyone

Answer 2

\[ 5 \sqrt{12k}\cdot 4k\sqrt{3} \]
everything is being multiplied, so you can change the order (because 2*3 is the same as 3*2, for example)
\[ 5\cdot 4k \sqrt{12k}\cdot\sqrt{3} \]
5 times 4 is 20, so you can simplify this to
\[ 20k \sqrt{12k}\cdot\sqrt{3} \]
you could "merge" the square roots because
\[ \sqrt{a\cdot b}= \sqrt{a} \cdot \sqrt{b} \] and vice versa
so you could write this as
\[ 20k \sqrt{3\cdot 12k} \]
or
\[ 20k \sqrt{36k} \]
can you continue ?