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Mathematics 7 Online
OpenStudy (anonymous):

3tan^3 x=tanx

OpenStudy (phi):

for ease of typing, let y = tan(x) then 3tan^3 x=tanx can be written as \[ 3 y^3 = y \] or, subtract y from both sides to get \[ 3y^3 - y=0\] factor out a y from both terms \[ y(3y^2-1) = 0\] can you solve for y?

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