Question

Please help!!
Darren designed this triangular shaped entrance, ABC, to a mall.

Which expression can be used to find the distance between the points B and C of the entrance?

15 (cot 65° + sec 25°)

15 by cot 65 degrees plus 15 by sec 25 degrees

15 by cot 65 degrees plus 15 by cot 25 degrees

15(cot 65° + cot 25°)

Answer 1

@jim_thompson5910 can you help me please with this one?

Answer 2

@Luis_Rivera please??

Answer 3

@love_jessika15 can you help me please

Answer 4

hint: find BD and DC individually

Answer 5

B?

Answer 6

what did you get for BD

Answer 7

BD is 15 ft

Answer 8

AD is 15 ft

Answer 9

BD is not 15 ft

Answer 10

?? i dont understand so would BD be 65 and DC be 25?

Answer 11

you need to use trig to find BD

Answer 12

use that link I gave you earlier

Answer 13

@jim_thompson5910 ok one sec

Answer 14

I'm looking and i still dont understand @jim_thompson5910

Answer 15

solve for x and tell me what you get

Answer 16

ok i will

Answer 17

@Data_LG2 i dont get it?

Answer 18

hint: tan = opp/adj and cot = adj/opp