Question

POLAR EQUATION!! HELP!
sketch:2sin(feta) please explain!

Answer 1

should that say r = 2sin(theta)?

Answer 2

yes

Answer 3

http://www.wolframalpha.com/input/?i=graph+r%3D2sin%28theta%29

Answer 4

but i need to know how to get the points
but that is a cool website

Answer 5

http://www.youtube.com/watch?v=X6M7yfH6w_Y

Answer 6

When \(\large \theta=0\), we're pointing out in this direction.How far out should our radius extend?

Well if we plug \(\large \theta=0\) into our function, we can solve for r.\[\large r=2\sin0 \qquad\to\qquad r=0\]So our radius would extend outward zero.

Answer 7

When theta is pi/4 we're pointing out in this direction.
Let's plug pi/4 into our function to see what distance our radius should be.\[\large r=2\sin(\pi/4) \qquad\to\qquad r=\sqrt2\]