can someone help me with area of a triangle
|dw:1375861872463:dw|
Something appears to be missing here.
i need to find the high and the base of the triangle
height
I'm confident that something is missing in the problem you posted unless it is a right triangle which it doesn't appear to be.
Is the triangle a right triangle?
there is dotted lines that the teacher put to make it a right but idk
No one will be able to help you unless you post everything.
|dw:1375855613575:dw| is it something like this, you're trying to draw?
yea but he used dotted lines
may be you wanna try drawing again..or posting a screen shot
ok
|dw:1375863106866:dw|
Are you sure that's correct as written?
yes i even looked it over again
im so lost on all of this math stuff
If it is correct as shown, then you should be able to use the formula for area of a triangle to solve: \[\text{Area}_{\triangle} = \frac{bh}{2}\]Inputting the proper values, you get: \[180 = \frac{(4x-16)(2x)}{2}\]
Now all you have to do is just solve for x properly.
ok thank you i got it right thanks for the first steps
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