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OpenStudy (anonymous):
Please quick help!!!
The sail of a boat is in the shape of a right triangle, as shown below.
Which expression shows the length, in meters, of the base of the sail?
7 cosec 50°
7 by sec 50
7 by cosec 50
7 cot 50°
13 years ago
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OpenStudy (anonymous):
13 years ago
OpenStudy (anonymous):
@mayankdevnani can you help
13 years ago
OpenStudy (mayankdevnani):
@brianjr227 what is sin50 degree(use formula)?
13 years ago
OpenStudy (mayankdevnani):
\[\huge \bf \sin=\frac{perpendicular}{hypotenuse}\]
13 years ago
OpenStudy (mayankdevnani):
so \[\huge \bf what~is~\sin50^{\circ}??\]
13 years ago
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OpenStudy (mayankdevnani):
@brianjr227 can you find out?
13 years ago
OpenStudy (anonymous):
how you solve sin50 though?
13 years ago
OpenStudy (anonymous):
is it A? or is that wrong
13 years ago
OpenStudy (mayankdevnani):
because \[\huge \sin50^\circ=\frac{base}{7}\]
that's why we use sin50
13 years ago
OpenStudy (mayankdevnani):
yeah. its A
13 years ago
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OpenStudy (mayankdevnani):
becuase opposite of sin is cosec.
\[\huge \bf \sin=\frac{1}{cosec}\]
13 years ago
OpenStudy (mayankdevnani):
understood? @brianjr227
13 years ago
OpenStudy (anonymous):
@mayankdevnani thanks!!! :) do you mind helping me with two problems that i can't figure out??
13 years ago
OpenStudy (mayankdevnani):
why not? i'll try my best :)
and welcome :)
13 years ago
OpenStudy (anonymous):
yea i do the reciprocal
13 years ago
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OpenStudy (mayankdevnani):
post your questions. @brianjr227
13 years ago
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