Question

solve 6sin2x+3

Answer 1

I think I know one Smart guy here... Who can surely help you , he is @mayankdevnani

Answer 2

I don't understand the problem, what is you are asking to be solved.

Answer 3

he wants x to be solved....
So just move 6 to the other side and take the inverse of sin and remember there will be 2 answers

Answer 4

i know he wants to solve this :-
\[\huge \bf 6\sin(2x)+3=0\]

Answer 5

am i right? @Kavish

Answer 6

yes dude ;)

Answer 7

good. so post your full question

Answer 8

\[\huge \bf 6\sin(2x)+3=0\]
\[\huge \bf 6\sin(2x)=-3\]
\[\huge \bf \sin2x=\frac{-3}{6}=\frac{-1}{2}\]

Answer 9

here some steps for your hint

Answer 10

@Kavish

Answer 11

Also do you need to leave it in a general form or should be answer is restricted to a domain?

Answer 12

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s09_qp_1.pdf


Num 4(ii)

Answer 13

@mayankdevnani .. those step i knw.. :P

but what next..?

Answer 14

\[x= \frac{ \sin ^{-1}(-\frac{ 1 }{ 2 }) }{ 2}\]