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A die is rolled 6 times. Find the probability P(of exactly 4 occurrences of 2). a. 0.39% c. 0.47% b. 2.6% d. 0.8%
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I think you can use the binomial theorem for probability \[\Large (nCr) p^r q^{n-r}\] p is the probability of success (chance of getting a 2), q is the probability of not getting a 2. r is the number of two's you want to get (exactly four). n is the total number of rolls.
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