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find all solutions of the equation tan3x+1=sec3x in the interval [0,2pi).
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is that \(\tan^3x\) or \(\tan3x\)?
3x
so if we clean this up we have: tan u + 1 = sec u
if we square both sides that might help us, but it tends to introduce a few false results to be weeded out
tan^2 + 1 + 2tan = sec^2 , but sec^2 = tan^2 + 1 tan^2 + 1 + 2tan = tan^2 + 1 2tan = 0 might be worth looking into
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well, thats one of them :)
hmm, might be the only one too |dw:1375879398309:dw|
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