What are the solutions for x in the proportion 2x+3/x = 2x/2.? A.) x = −1 and x = 3 B.) x = 1 and x = −3 C.) x = −2 and x = 3 D.) x = 2 and x = −3
I think you equation is wrong.
no its right
*your Can you use the Equation tool?
\[2x +3divx =2x \div2\]
2x+3/x = 2x/2 multiply by x 2x^2 + 3 = 2x^2 / 2 2x^2 + 3 = x^2 2x^2 + 3 - x^2 = 0 x^2 = -3 x = Sqrt(-3) Can't square root a negative for your purpose. That is if your equation is this: \[2x + \frac{ 3 }{ x } = \frac{ 2x }{ 2 }\]
so is it d
Multiply by x and simplify \[2x ^{2}+3 = x ^{2}\] \[2x ^{2}+3-x ^{2}=0\] \[x ^{2}=-3\] No. Your equation is wrong.
Take square root both sides and you get Sqrt (-3). Can't get an answer that way.
ok I c what ur saying thank u now I no what happened
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