Question

can anybody please help me with this?

Answer 1

9=3*3
so u can mul num and den by 3 and you will have 3^3 in den and 3^2 in num . by cubing you would have 3 in den and cube(9) in num.

Answer 2

\[\sqrt[3]{\frac{ 3*3 }{ 3*3*3 }}\]

Answer 3

how do I continue? :(

Answer 4

I got B because 3sqrt(3/9) = 3 and sqrt(3) / sqrt(9) and then you multiply
3 and sqrt(3) / sqrt(9) * sqrt(9) / sqrt(9) you get 3sqrt(27) / 9 you get 3sqrt(3)/ 3

Answer 5

sorry if you cannot read it well

Answer 6

I cannot understand what you did:(