Projectile/ Trig Question, please help!

Recall that the equation for horizontal distance h in feet of a projectile with initial velocity v(subscript)0 and initial angle θ is given by h = (v(subscript)0 ^2 /16)sin θ cos θ.

Assume the initial velocity is 60 ft/sec. What is the maximum horizontal distance possible and at what angle does this occur?

PLEASE PLEASE HELP! medal given!

Question

Projectile/ Trig Question, please help!

Recall that the equation for horizontal distance h in feet of a projectile with initial velocity v(subscript)0 and initial angle θ is given by h = (v(subscript)0 ^2 /16)sin θ cos θ.

Assume the initial velocity is 60 ft/sec. What is the maximum horizontal distance possible and at what angle does this occur?

PLEASE PLEASE HELP!  medal given!

psymon · Answer

Is that supposed to be (2/1^)*sin(theta)cos(theta)? I can't tell what its supposed to be x_x

psymon · Answer

(2/16) I meant, lol.

avanti · Answer

no it looks like |dw:1375905512358:dw|