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find the sum of the first 10 terms of the series 2-6+18-54+...
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have you studied arithmetic and geometric progressions?
@kat762 if you have, then try and spot what type of series this is: 2, -6, 18, -54, ...
you have an geometric series . The difference is a2 /a1 = -6/2 = -3 sn = a1 (1 - r^n)/(1 - r) n = 10 a1 = 2 (first term) r = -3
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