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Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0 Please don't just answer I just need help on how to start it.
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Well, logically, the only way you can multiply and get zero is if one of the numbers involved in the multiplication is itself 0. So you can either have sinx = 0 or cosx = 0. So what are all the values in which either of those two situations occurs?
umm 0 is one pi/2
does are two right?
Yep, now two more.
pi and 3pi/2?
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You got it :P
wow thanks that was kinda easy i guess thanks alot!
Yeah, that one wasn't as bad compared to others xD
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