Question

(X+5)^2-12(X+5)+32=0
SOLVE THIS EQUATION BY USING THE QUADRATIC FORM

Answer 1

Well, do it!

\((x+5) = What?\)

Answer 2

-5

Answer 3

WHAT ABOUT THE REST OF IT

Answer 4

You have used the Quadratic Formula, right?

What would you do if it said \(z^{2} - 12z + 32 = 0\)?

Answer 5

I'D FACTOR RIGHT (Z-8)(Z-4)

Answer 6

Z=8,4

Answer 7

I suppose you could do that. Are we supposed to use the Quadratic Formula?

Anyway, your factoring is fine. Do this problem EXACTLY the same way. Just write "x+5" instead of "z".

Answer 8

X+5-8
X+5-4

Answer 9

X=-3,1?

Answer 10

You're almost done. Write "= 0" and solve. You missed some signs. Write THE ENTIRE equation before attempting to solve.

(X+5) - 8 = 0
(X+5) - 4 = 0

Answer 11

(X+5)=8
X=3?
(X+5)=4
X=-1

Answer 12

Good work. It helps to write it ALL! :-)

Answer 13

THANKS

Answer 14

(X-4)^2+4(X-4)-12=0
X^2+4X-12
(X+6)(X-2)
X=-6,2
(X-4)-6=0
(X-4)+2=0
X-4=6...X=10?
X-4=-2....X=2?

Answer 15

Pretty good, but it is confusing when you use the same variable name.

You have X-4 and you changed to X. Better to change to Z or something other than X.