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Mathematics 7 Online
OpenStudy (anonymous):

How do you simplify √x³ ÷ ³√x⁴

OpenStudy (anonymous):

Its of the form x3/2÷x4/3

OpenStudy (anonymous):

Its of the form x^(3/2)-(4/2)...........Can u cntnu??

OpenStudy (anonymous):

\[\sqrt{x \times x ^{2}}=x \sqrt{x}\] \[\sqrt[3]{x4}=\sqrt[3]{x \times x ^{3}}=x \times \sqrt[3]{x}\]

OpenStudy (anonymous):

\[x ^{3/2} \div x^{4/3}\]

OpenStudy (anonymous):

@myunqsoo Did u get it????

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Well...The rule is a^x/a^y=a^(x-y)...Now do u get it??

OpenStudy (anonymous):

\[\sqrt{x ^{3}} ..is.. simply.... x^{3/2} \]

OpenStudy (anonymous):

OpenStudy (anonymous):

Similarly \[\sqrt[3]{x^4}.....is ...simply... x^{4/3}\]

OpenStudy (anonymous):

@Imtiaz7 ...M afraid ur wrong!!

OpenStudy (anonymous):

@myunqsoo Wat value do u get when u subtract 4/3 from 3/2??

OpenStudy (imtiaz7):

in division powers are subtracted

OpenStudy (anonymous):

- 1/6

OpenStudy (imtiaz7):

@cambrige i made a mistake

OpenStudy (anonymous):

Ya....but u took down the question wrong @Imtiaz7 !!Cheers!

OpenStudy (anonymous):

Are u sure its -1/6 @myunqsoo ??

OpenStudy (anonymous):

REcheck ur ans...@myunqsoo :)

OpenStudy (anonymous):

@myunqsoo

OpenStudy (anonymous):

1/6?

OpenStudy (anonymous):

\[x^{1/3} ....is.....same..as..\sqrt[3]{x}.\]

OpenStudy (anonymous):

How did u get 12 @Imtiaz7 ??

OpenStudy (anonymous):

Yes u r correct @myunqsoo

OpenStudy (anonymous):

\[x^{1/3}....is.....same..as ...\sqrt[3]{x}.\]

OpenStudy (anonymous):

.Wat do u think \[x^{1/6}\] shud be written as??

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

6√x

OpenStudy (anonymous):

with a small 6

OpenStudy (anonymous):

Abra Ca Dabra......There u go!!

OpenStudy (anonymous):

ohh okay thank you!!

OpenStudy (anonymous):

U r 100% +1 correct!!

OpenStudy (anonymous):

Ur Welcome.Happy 2 Help!!

OpenStudy (anonymous):

haha thanks again!! :)

OpenStudy (anonymous):

NP.......:)

OpenStudy (anonymous):

omg i forgot how to count.

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