Mathematics
7 Online
OpenStudy (anonymous):
How do you simplify √x³ ÷ ³√x⁴
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OpenStudy (anonymous):
Its of the form
x3/2÷x4/3
OpenStudy (anonymous):
Its of the form
x^(3/2)-(4/2)...........Can u cntnu??
OpenStudy (anonymous):
\[\sqrt{x \times x ^{2}}=x \sqrt{x}\]
\[\sqrt[3]{x4}=\sqrt[3]{x \times x ^{3}}=x \times \sqrt[3]{x}\]
OpenStudy (anonymous):
\[x ^{3/2} \div x^{4/3}\]
OpenStudy (anonymous):
@myunqsoo Did u get it????
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
Well...The rule is a^x/a^y=a^(x-y)...Now do u get it??
OpenStudy (anonymous):
\[\sqrt{x ^{3}} ..is.. simply.... x^{3/2} \]
OpenStudy (anonymous):
OpenStudy (anonymous):
Similarly \[\sqrt[3]{x^4}.....is ...simply... x^{4/3}\]
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OpenStudy (anonymous):
@Imtiaz7 ...M afraid ur wrong!!
OpenStudy (anonymous):
@myunqsoo Wat value do u get when u subtract 4/3 from 3/2??
OpenStudy (imtiaz7):
in division powers are subtracted
OpenStudy (anonymous):
- 1/6
OpenStudy (imtiaz7):
@cambrige i made a mistake
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OpenStudy (anonymous):
Ya....but u took down the question wrong @Imtiaz7 !!Cheers!
OpenStudy (anonymous):
Are u sure its -1/6 @myunqsoo ??
OpenStudy (anonymous):
REcheck ur ans...@myunqsoo :)
OpenStudy (anonymous):
@myunqsoo
OpenStudy (anonymous):
1/6?
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OpenStudy (anonymous):
\[x^{1/3} ....is.....same..as..\sqrt[3]{x}.\]
OpenStudy (anonymous):
How did u get 12 @Imtiaz7 ??
OpenStudy (anonymous):
Yes u r correct @myunqsoo
OpenStudy (anonymous):
\[x^{1/3}....is.....same..as ...\sqrt[3]{x}.\]
OpenStudy (anonymous):
.Wat do u think \[x^{1/6}\] shud be written as??
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OpenStudy (anonymous):
oh
OpenStudy (anonymous):
6√x
OpenStudy (anonymous):
with a small 6
OpenStudy (anonymous):
Abra Ca Dabra......There u go!!
OpenStudy (anonymous):
ohh okay thank you!!
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OpenStudy (anonymous):
U r 100% +1 correct!!
OpenStudy (anonymous):
Ur Welcome.Happy 2 Help!!
OpenStudy (anonymous):
haha thanks again!! :)
OpenStudy (anonymous):
NP.......:)
OpenStudy (anonymous):
omg i forgot how to count.