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OpenStudy (anonymous):
Do you understand ot are you completely lost?
OpenStudy (anonymous):
iam completely lost
OpenStudy (anonymous):
well do you know what exact solutions are?
OpenStudy (anonymous):
solutions to the equation I think
OpenStudy (anonymous):
well sorta (want me to explain?)
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OpenStudy (anonymous):
yeah please
OpenStudy (anonymous):
As used in physics, the term "exact" generally refers to a solution that captures the entire physics and mathematics of a problem as opposed to one that is approximate, perturbative, etc. Exact solutions therefore need not be closed-form.
OpenStudy (anonymous):
should I put up the answers
OpenStudy (anonymous):
yes plz do
OpenStudy (anonymous):
hey hold on ill be right back im bout to change my picture i look old in this one
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OpenStudy (anonymous):
x = the quantity of negative 5 plus or minus the square root of 3 all over 2
x= the quantity of 5 plus or minus the square root of 3 all over 2
x = the quantity of negative 5 plus or minus the square root of 53 all over 2
x = the quantity of 5 plus or minus the square root of 53 all over 2
OpenStudy (anonymous):
x=\[x={\frac{ 5 \pm \sqrt(53) }{ 2 }}\]
OpenStudy (anonymous):
howd u get that
OpenStudy (anonymous):
if equation is \[ax^2+bx+c=0\] then solutions of it iare \[\frac{ -b \pm \sqrt(b^2-4ac) }{ 2a }\]
OpenStudy (anonymous):
oh ok I kinda get it now
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