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OpenStudy (anonymous):
To what value does the series coverge to: series from 1 to infinity of n/(n^2+1)^2
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OpenStudy (anonymous):
I did the integral test and got 1/4
OpenStudy (amistre64):
\[\sum_1\frac{n}{n^4+2n^2+1}\] well, its not 1/4 exactly
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